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 SIMPLE MOVEMENT
 


Eeach bunch travels at almost the speed of light (v = 0,999999991·c ) :

v = 0,999999991 x 299792458     v = 299792455 m/s

So each one will go around

299792455 / 26659 = 11245 laps per second

During the 20 minutes needed to reach the final energy, the protons cover a distance further than from Earth to the Sun and back.

11245 x 20 x 60 x 27 = 3.64·108 km

The Frequency of the circular movement already calculated is: f = 11,245 kHz

And the Period is: T = 1/f 9·10-5 s

Protons will be  accelerated to v~c.  While travelling they will permanently be under a centripetal acceleration produced by Lorentz Force.

Let´s calculate this centripetal acceleration:

c2/r   ⇒  ac 2.3·1013 m/s2

Therefore 2·1012 times the acceleration of gravity.


It's been said before that the distance between the two bunches will be : d = 7, 48 m

So the “time between bunches” -bunch spacing-  will be

t = distance / velocity
t = 7,48 / 3·108

t = 24,95·10-9 s     t = 24,95 ns
which is a very important parameter.

Another interesting exercise is to calculate how many laps the protons travel before falling due to gravity.
h = ½g·t2     t =  (2h/g)1/2
where h  is the pipe radius (~ 28 mm)

so: t = (2·0,028/9,81)1/2

  t ≈ 76 ms

Divided by the period:

nº of laps = 76·10-3/8,9·10-5

n = 850 laps

Therefore, we must not only correct the electromagnetic alterations but we must also correct those due to gravity. The magnetic multipoles will correct those alterations.



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