
How much energy are we talking about?
7 TeV = 7·10^{12 }eV · 1,6·10^{19} J/eV = 1,12·10^{6} J
It doesn´t look like a lot of energy
For the ALICE experiment, each ion of Pb208 reaches 1150/2 = 575 TeV.
So, the energy per nucleon is: 575/208 = 2,76 TeV

Let´s calculate the kinetic energy of an insect of 60 mg flying at 20 cm/s:
E_{k} = ½ m·v^{2} ⇒ E_{k} = ½ 6·10^{5}·0,2 ^{2} ~ 7 TeV
That is, in LHC each proton will reach an energy similar to that of an annoying ... MOSQUITO!
But we have to keep in mind that this mosquito has 36 thousand trillion nucleons, whereas the 7 TeV in the LHC will be concentrate in one sole proton.



Maybe this comparison is not very convincing so let´s look at it from another point of view.
Let´s calculate the energy present in each bunch:
7 TeV/protón·1,15·10^{11} protons/bunch ~ 1,29·10^{5} J/bunch
A powerful motorbike 150 kg travelling at 150 km/h_
E_{k} = ½ ·150 · 41,7^{2} ~ 1,29·10^{5} J


So if a bunch of protons collides with you the impact is similar to that produced by a powerful motorbike travelling at 150 km/h.
If you are lucky to avoid that "0,2 picogram motorbike", don´t worry, there are 2807 following it. And if you decide to change lanes, the equivalent is coming in the opposite direction.

Another calculation which can show the enormous amount of energy reached is:
1,29·10^{5} J / bunch x 2808 bunches ~ 360 MJ

And that is equivalent to
77,4 kg of TNT
The energy content of TNT is 4.68MJ/kg (Beveridge 1998).

The Heat of Fusion of Gold is: ΔH_{F} = 63,71 kJ/kg
So, 360 MJ are enough to melt: 5650 kg ⇒ 5,65 Tonnes of gold.
Obviously such an amount of energy can not be supplied instantly. In fact the process lasts over 20 min through a chain of different accelerators.

